Torque equations:

$\overline{){\mathbf{\tau}}{\mathbf{=}}{\mathbf{rFsin\theta}}}$

We just need to plug and chug in the torque equation.

A 95 N force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of 15 N•m. What is the angle (assumed to be less than 90°) between the wrench handle and the direction of the applied force?

A) 22°

B) 14°

C) 18°

D) 25°

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What scientific concept do you need to know in order to solve this problem?

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