| Structure and Oxidataion no. |
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asutoshsahu
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Joined: 11 Oct 2005
Posts: 5
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 Posted: Sat Mar 11, 2006 7:45 am Post subject: Structure and Oxidataion no. |
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What is the structure of Na2S4O6
IN THIS MOLECULE WHAT IS THE OXIDATION NO. OF SULPHER.
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opuntia
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Joined: 15 Jun 2005
Posts: 82
Location: Maldives(the chain of islands)
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| Posted: Mon Mar 13, 2006 9:03 am Post subject: |
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Here are some hints,
Oxidation number of group one metals is +1
Oxidation number of oxygen is -2
The sum of all the oxidation numbers of a neutral molecule is equal to zero.
Now try on your own and just let us know the answer you get. 
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asutoshsahu
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Joined: 11 Oct 2005
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| Posted: Tue Mar 14, 2006 7:44 am Post subject: |
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In Na2S4O6
Na +1
O -2
Then 1x2+4S+(-2)x6=0
Soving this we get O.N. of S=2.5
But in a book it is given that in this molecule two S atom has O.N. +5 (i.e. 5+5 = 10 ) and the other two S has zero O.N.
Any comments on this.....
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opuntia
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Joined: 15 Jun 2005
Posts: 82
Location: Maldives(the chain of islands)
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| Posted: Tue Mar 21, 2006 8:11 am Post subject: |
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What your book says...  never seen anything like that before!
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guanine
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Joined: 20 Mar 2006
Posts: 35
Location: Santa Cruz, California
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| Posted: Wed Mar 22, 2006 7:13 pm Post subject: |
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| I'm not 100% sure about this, but I think that in this compound, Na2S4O6, has three O2 2- groups. The oxygen atoms in an O2 2- group have oxidation states of -1; therefore, the oxidation states of the sulfur would be 2.
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Carib eyez
A really tough bot, or a member.
Joined: 20 Feb 2006
Posts: 2
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| Posted: Wed Mar 22, 2006 7:37 pm Post subject: |
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[quote="asutoshsahu"]In Na2S4O6
Na +1
O -2
Then 1x2+4S+(-2)x6=0
Soving this we get O.N. of S=2.5[quote]
That's how I work it out thusthe answer is 2.5
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guanine
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Location: Santa Cruz, California
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| Posted: Wed Mar 22, 2006 8:43 pm Post subject: |
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I've never heard of an oxidation state that isn't an interger.   If there can be non-interger oxidation states, please inform me. I'm gonna ask my teacher about it as well.
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asutoshsahu
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Joined: 11 Oct 2005
Posts: 5
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| Posted: Sat Mar 25, 2006 10:16 am Post subject: |
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Hey I have got the answer .
I am sending a image file and see how the two S has O.N. +5 and the rest two zero
The two sulfurs shown in red are each bonded to three oxygens and one sulfur, for an oxidation of +3; but they also carry a +2 formal charge, so their oxidation state is +5. On the other hand, the two sulfurs shown in blue are bonded only to sulfur, and have no formal charge; their oxidation state is 0 (zero). The total oxidation states of the four sulfur atoms is 5 + 5 + 0 + 0 = 10, or an average of +2.5.
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opuntia
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Joined: 15 Jun 2005
Posts: 82
Location: Maldives(the chain of islands)
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| Posted: Mon Mar 27, 2006 6:14 am Post subject: |
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| guanine wrote: |
| I've never heard of an oxidation state that isn't an interger. If there can be non-interger oxidation states, please inform me. I'm gonna ask my teacher about it as well. |
I asked my teacher and she said that it is possible for an element to have an oxidation number which is not an integer.
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