Fe2+(aq) + MnO4-(aq)
Fe3+(aq) + Mn2+(aq) (acidic solution)
1. Write the half reactions:
Fe2+(aq)
Fe3+(aq) (oxidation)
MnO4-(aq)
Mn2+(aq) (reduction)
2. Balance each half reaction:
Fe2+(aq)
Fe3+(aq) + e-
MnO4-(aq) + 8H+(aq) + 5e-
Mn2+(aq) + 4H2O
3. Combine the half reactions to give the overall reaction:
5Fe2+(aq)
5Fe3+(aq) + 5e-
MnO4-(aq) + 8H+(aq) + 5e-
Mn2+(aq) + 4H2O
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5Fe2+(aq) + MnO4-(aq) + 8H+(aq)
5Fe3+(aq) + Mn2+(aq) + 4H2O
Try balancing the lead-acid battery reaction:
Pb(s) + PbO2 (s) + SO42-(aq)
PbSO4(s)
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