WHat elements can produce Carbon Dioxide?

Which of the following mixtures would be most likely to produce carbon dioxide? and why?



A. magnesium and nitric acid

B. sodium carbonate and sulfuric acid

C. hydrogen peroxide and copper

[chemteacher]

it is the only one with c in it to start with....

[Hix3r]

obviously B is the right answer, as said these are the only materials that have carbon in them...

A: Mg + HNO3 -> Mg(NO3)2 + H2

B: Na2CO3 + H2SO4 -> Na2SO4 + CO2 + H2O

C: H2O2 + Cu -> Cu(OH)2 i guess, but dont know

other two does not even have carbon in them...

[Hawk392]

Yes, Hix3r would be correct, the only answer that would be most likely to produce CO2 would HAVE to be sodium carbonate and sulfiric acid, since, as forementioned, those two compounds are the only ones that have Carbon in them.

NaCO3 + H2SO4 => NaSO4 + CO2 + H2O

After this reaction is complete, you are left with your Sodium Carbonite, Carbon Dioxide, and Water. The only thing I disagree with when it comes to Hix3r's answer is that Na does not have a 2 as a subscript in Sodium Carbonate, Sodium is not diatomic, and therefore doesn't need multiple sodiums. Plus, if it WERE diatomic, it would be binding to your CO3, and wouldn't need another sodium molecule in it.

But to answer your question in the first place, your answer choice should be B, since as shown above, CO2 is a product of your Sodium Carbonate and Sulfiric Acid.

[Hix3r]

I used to mix that up, but after several times I learned it.

Sodium-carbonate looks like this:

Na2CO3 because Na ions have +1 charge and CO3 ions have -2 charge. You can check it out here:

http://en.wikipedia.org/wiki/Sodium_carbonate

Sodium-sulfate:

Na2SO4 because Na ions have +1 charge and SO4 ions have -2 charge. Also check it out here:

http://en.wikipedia.org/wiki/Sodium_sulfate

Anyway you can see this from the acids if you know them better. H2SO4 is sulfuric acid, H has the exact same charge as an ion as Na. So just replace it. Na2SO4. H2CO3 is carbonic acid, again just replace H with Na. Na2CO3.
Try to get a hang of it, and you won't mix it up anymore.

[Hawk392]

Ah thanks for the correction. I'm always open to being corrected if I'm wrong.

Anyway, I think that by now your question has been answered between me and Hix3r here. I'm glad that I could've been of some assistance (if I was to you that is) :P.