I need help setting up a conversion problem

Hello all I am new here and I need help setting up the conversion to this problem. If anyone can help please let me know.

The problem is: During the summertime in Atlanta, the jet stream moves north towards Canada, and the atmosphere often stagnates. Weather forecasters give daily ozone warnings to the elderly and to people with asthma because ozone build-up in the air is harmful. Typically, an adult will in hale 2.1 liters of air per breath. What mass of ozone in micrograms is taken into the lungs per breath by an adult breathi8ng air containing 3.64 x 10 to the negative 4, of ozone per cubic centimeter of air?

Thank you.

[Hix3r]

The adult breathes in 2.1 litre of air which is 2.1 dm^3 and this is 2100 cm^3.

So I take it that you wanted to tell the mol concentration of ozone 3.64*10^-4 mol/cm^3...

In 1 cm^3 there is 3.64*10^-4 mol
In 2100 cm^3 there is 2100*3.64*10^-4 mol = 0.7644 mol of ozone.

1 mol of ozone is 3*16 g.
0.7644 mol is 0.7644*3*16 g = 36.69 g Which is pretty scary.

So during summertime in Atlanta an adult can inhale 36.7 g of ozone per breath.