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#1
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If you have two baloons of equal volume at the same temperature and pressure, one containing helium and one containing methane, how do their masses compare?
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#2
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Another question: What volume would occupy .100 moles of oxygen gas at STP? What about two moles?
And What are the STP conditions in relation to volumes of gases? :?: |
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#3
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you only need this:
p*V=n*R*T p.. pressure V.. Volume n.. moles of gas R.. Gasconstant T.. temperature all in SI n = m/M where as M is g/mol and m is g |
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#4
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Use pV = nRT outside of STP. At STP one mole of any gas has 22.4L. Always.
Best, Borek |
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#5
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The problem suggests equimolar amounts of the two gases, however their masses will differ since the molar mass is not the same.
PV=nRT n=PV/RT, n=moles molar mass=grams/mole thus you have n x (Mhelium) and n x (Mmethane)=mass helium and methane respectively, where M=molar mass. The ratio of masses turns out to be the ratio of molar masses. |
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