#1




Structure and Oxidataion no.
What is the structure of Na2S4O6
IN THIS MOLECULE WHAT IS THE OXIDATION NO. OF SULPHER. 
#2




Here are some hints,
Oxidation number of group one metals is +1 Oxidation number of oxygen is 2 The sum of all the oxidation numbers of a neutral molecule is equal to zero. Now try on your own and just let us know the answer you get. 
#3




In Na2S4O6
Na +1 O 2 Then 1x2+4S+(2)x6=0 Soving this we get O.N. of S=2.5 But in a book it is given that in this molecule two S atom has O.N. +5 (i.e. 5+5 = 10 ) and the other two S has zero O.N. Any comments on this..... 
#4




What your book says... :shock: never seen anything like that before!

#5




I'm not 100% sure about this, but I think that in this compound, Na2S4O6, has three O2 2 groups. The oxygen atoms in an O2 2 group have oxidation states of 1; therefore, the oxidation states of the sulfur would be 2.

#6




[quote="asutoshsahu"]In Na2S4O6
Na +1 O 2 Then 1x2+4S+(2)x6=0 Soving this we get O.N. of S=2.5[quote] That's how I work it out thusthe answer is 2.5 
#7




I've never heard of an oxidation state that isn't an interger. :? :?: If there can be noninterger oxidation states, please inform me. I'm gonna ask my teacher about it as well.

#8




Hey I have got the answer .
I am sending a image file and see how the two S has O.N. +5 and the rest two zero The two sulfurs shown in red are each bonded to three oxygens and one sulfur, for an oxidation of +3; but they also carry a +2 formal charge, so their oxidation state is +5. On the other hand, the two sulfurs shown in blue are bonded only to sulfur, and have no formal charge; their oxidation state is 0 (zero). The total oxidation states of the four sulfur atoms is 5 + 5 + 0 + 0 = 10, or an average of +2.5. 
#9




Quote:

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