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#1
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How many grams of air would be in an otherwise empty 2.00-liter beverage container at a pressure of 750 torr and temperature of 27 °C? Since air is about one-fifth oxygen and four-fifths nitrogen, we often treat it as a single gas with an average molar mass of 29 g/mol.
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#2
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Again we have to use this formula:
p*V = n*R*T p in Pa... 750 torr = 99991.78 Pa V in cubic metres = 0.002 m3 R is a constant = 8.3145 whatever T is in Kelvin = 300.15 K n = (99991.78*0.002)/(8.3145*300.15) = 0.08 mol So we have 0.08 mol gas in the bottle, and we know the molar mass. 1 mol of the gas is 29 g. So 0.08 mol of the gas is 29*0.08 mol = 2.32 g of air. Pretty light huh? |
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