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Old April 9th, 2006, 22:06
moni moni is offline
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A sample of 25.0ml of 0.10 M lactic acid (HC3H5)3 , pKa =3.850 is titrated with 0.10 NaOH aquation solution. What is the volume of the base needed to reach equivalence point?what is the Ph at the equivalance point? help please!!!!!!!!!
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Old April 10th, 2006, 17:35
Borek Borek is offline
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Once you will sove the formic acid question this one will be a breeze

Besides, these calculations are descibed in the pH cheat sheet, you just have to understand what you have to calculate.
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Old April 18th, 2006, 01:11
RobJim RobJim is offline
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Volume of acid solution => moles of acid => moles of base => volume of base is the process for the first part. The second part requires some equation; can't remember off the top of my head. Henderson-Hasselbach?
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Old April 20th, 2006, 16:12
Deronius Deronius is offline
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Just use some bromthymol blue as a Ph indicator.
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Old May 5th, 2006, 15:27
rctrackstar2007 rctrackstar2007 is offline
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Use the indicator to know when you've reached the equivalence point. The use: pH=pKa + log([H+]/[HA](undisociated acid))

I believe that is how you do it.
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Old May 6th, 2006, 04:41
Borek Borek is offline
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Quote:
Originally Posted by RobJim
The second part requires some equation; can't remember off the top of my head. Henderson-Hasselbach?
No, HH can be used before equivalence point. At equivalence you have just a solution of sodium lactate - salt of weak acid and strong base, so you calculate pH from lactate hydrolyzis.

Check titration curve calculation lecture.
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