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#1
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When (2S,3S)-3-bromo-2-methoxybutane undergoes an Sn2 reaction with methoxide ion, the product is not optically active. Why is that??
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#2
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Well, the methoxy ion, CH3O(-), will perform a backside attack on carbon-3, displacing the bromine. This will form a substance identical to it's enantiomer. What is that molecule?
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