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Old May 19th, 2005, 14:40
pussnboots pussnboots is offline
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Default Help on Finals Study Packet!!!!

If you have two baloons of equal volume at the same temperature and pressure, one containing helium and one containing methane, how do their masses compare?
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Old May 19th, 2005, 14:44
pussnboots pussnboots is offline
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Another question: What volume would occupy .100 moles of oxygen gas at STP? What about two moles?



And What are the STP conditions in relation to volumes of gases? :?:
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Old May 25th, 2005, 06:31
Nick Nick is offline
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you only need this:

p*V=n*R*T

p.. pressure
V.. Volume
n.. moles of gas
R.. Gasconstant
T.. temperature

all in SI

n = m/M where as M is g/mol and m is g
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Old May 25th, 2005, 08:59
Borek Borek is offline
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Use pV = nRT outside of STP. At STP one mole of any gas has 22.4L. Always.

Best,
Borek
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Old May 25th, 2005, 15:54
GCT GCT is offline
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The problem suggests equimolar amounts of the two gases, however their masses will differ since the molar mass is not the same.

PV=nRT

n=PV/RT, n=moles

molar mass=grams/mole

thus you have n x (Mhelium) and n x (Mmethane)=mass helium and methane respectively, where M=molar mass.

The ratio of masses turns out to be the ratio of molar masses.
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