can someone check my simple equation please

[mummyjojo]

right im really not very good at this so would someone please check this for me and tell me if its right or wrong....


an unknown metal known as M forms a soluble hydroxide with the formula M(OH)2

if this is immersed in water

M(OH)2 + H2O ----MH4O3

is this right?
someone please help

[Hix3r]

Some basic principles may be missing or I don't know, but why would an unknown metal-hydroxyde take up more water?
Anyway M(OH)2 so it rules out all metals in the first group (from hydrogen to francium), also rules out aluminium. But it's not the point.

If a metal hydroxyde is soluble in water, it will disintegrate into ions, therefore making the solution basic. It hydrolyzes.

M(OH)2 -> M2+ + 2 OH-

Certainly won't pick up more water.
The other thing is also entirely wrong.

M(OH)2 + H2O = M2(OH)2

This is not a equation to begin with. You have different amounts of materials on the two sides! Things don't disappear and appear from air! From where does the second metal atom come from? and where does the H2O molecule go? Because if I count this, 4 H, 3 O and 1 M atom are on the left side and 2 H, 2 O and 2 M atoms are on the right side. Water transformed into a metal atom???...

Anyway, if a metal-hydroxyde is soluble in water it will most likely hydrolyze and separate into ions. Therefore NaOH, Ca(OH)2, etc. solutions are basic.

[KathChem82]

hi! it's true that the metal does not belong to group 1. It does not belong to group 13 either. It belongs to group 2. It could be magnesium, calcium, etc. M here has an oxidation state of +2 and OH has -1. Metal hydroxides of the group 2 elements are usually soluble in water, making the solution basic due to the production of OH- anions as this metal ionizes into OH- and Ma+2.