Structure and Oxidataion no.
 User Name Remember Me? Password

#1
March 11th, 2006, 01:45
 asutoshsahu Junior Member Join Date: Oct 2005 Posts: 3
Structure and Oxidataion no.

What is the structure of Na2S4O6

IN THIS MOLECULE WHAT IS THE OXIDATION NO. OF SULPHER.
#2
March 13th, 2006, 03:03
 opuntia Member Join Date: Jun 2005 Location: Maldives(the chain of islands) Posts: 55

Here are some hints,
Oxidation number of group one metals is +1
Oxidation number of oxygen is -2
The sum of all the oxidation numbers of a neutral molecule is equal to zero.

Now try on your own and just let us know the answer you get.
#3
March 14th, 2006, 01:44
 asutoshsahu Junior Member Join Date: Oct 2005 Posts: 3

In Na2S4O6
Na +1
O -2
Then 1x2+4S+(-2)x6=0
Soving this we get O.N. of S=2.5

But in a book it is given that in this molecule two S atom has O.N. +5 (i.e. 5+5 = 10 ) and the other two S has zero O.N.

Any comments on this.....
#4
March 21st, 2006, 02:11
 opuntia Member Join Date: Jun 2005 Location: Maldives(the chain of islands) Posts: 55

What your book says... :shock: never seen anything like that before!
#5
March 22nd, 2006, 13:13
 guanine Member Join Date: Mar 2006 Location: Santa Cruz, California Posts: 23

I'm not 100% sure about this, but I think that in this compound, Na2S4O6, has three O2 2- groups. The oxygen atoms in an O2 2- group have oxidation states of -1; therefore, the oxidation states of the sulfur would be 2.
#6
March 22nd, 2006, 13:37
 Carib eyez Junior Member Join Date: Feb 2006 Posts: 1

[quote="asutoshsahu"]In Na2S4O6
Na +1
O -2
Then 1x2+4S+(-2)x6=0
Soving this we get O.N. of S=2.5[quote]

That's how I work it out thusthe answer is 2.5
#7
March 22nd, 2006, 14:43
 guanine Member Join Date: Mar 2006 Location: Santa Cruz, California Posts: 23

I've never heard of an oxidation state that isn't an interger. :? :?: If there can be non-interger oxidation states, please inform me. I'm gonna ask my teacher about it as well.
#8
March 25th, 2006, 04:16
 asutoshsahu Junior Member Join Date: Oct 2005 Posts: 3

Hey I have got the answer .
I am sending a image file and see how the two S has O.N. +5 and the rest two zero

The two sulfurs shown in red are each bonded to three oxygens and one sulfur, for an oxidation of +3; but they also carry a +2 formal charge, so their oxidation state is +5. On the other hand, the two sulfurs shown in blue are bonded only to sulfur, and have no formal charge; their oxidation state is 0 (zero). The total oxidation states of the four sulfur atoms is 5 + 5 + 0 + 0 = 10, or an average of +2.5.
#9
March 27th, 2006, 00:14
 opuntia Member Join Date: Jun 2005 Location: Maldives(the chain of islands) Posts: 55

Quote:
 Originally Posted by guanine I've never heard of an oxidation state that isn't an interger. :? :?: If there can be non-interger oxidation states, please inform me. I'm gonna ask my teacher about it as well.
I asked my teacher and she said that it is possible for an element to have an oxidation number which is not an integer.

 Thread Tools Display Modes Linear Mode

 Posting Rules You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is Off Forum Rules
 Forum Jump User Control Panel Private Messages Subscriptions Who's Online Search Forums Forums Home Science, Technology & Devices     General Discussion     Periodic Table     Organic Chemistry

All times are GMT -5. The time now is 08:52.

 Contact Us - Periodic Table - Archive - Top

Powered by vBulletin® Version 3.8.7
Copyright ©2000 - 2014, vBulletin Solutions, Inc.