Help with enthalpy
1. The bombardier beetle uses the following explosive reaction as a defence mechanism. The product acts as a repellent.
C6H4(OH)2 + H202 -> C6H4O2 + 2 H20
Calculate the enthalpy change for the above reaction using the following information equations.
1. C6H4O2 + H2 -> C6H4(OH)2 delta Hr = -177.4 kJ
2. 2 H20 + H2 -> O2 + 2 H20 delta Hr = -189.0 kJ
3. 1/2 O2 + H2 -> H20 delta Hr = -285.8kJ
I understand that we have to come out with the net equation, but somehow my calculations aren't able to cross components out.
So you think you might be able to help me, and if so show me the work?
Thank you.[/img]
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