2.0 mL is 0.00020 L, not 0.0020 L.
You correctly identified iron (II) phosphate as the precipitate. However phosphate as a -3 charge, and your equation suggests it has a -1 charge.
You also need to independently determine the moles of iron (II) and phosphate ion and figure out which one will run out first; in other words, which is the limiting reagent. To do this you need to take into account how many Fe2+ ions will react with how many phophate ions as well as the number of moles of each.
Then, once you've determined which one is the limiting reagent, you can figure out how many moles of precipitate there will be, and from there what the mass of the precipitate will be.
|