Destroying with HCl means reacting all sodium acetate.
3.3g=0,024 moles sodium acetate.
We will assume that the final buffering solution have 50mL.
Therefore 19 mL involve 19/50*0.024=0.009 moles. we need 0.009 mole of HCl.
May I approximate to 0.01 mole? Thank you.
Now, HCl is at your choice. Pure HCl is gaseous, then we need an aqeuous solution.
The most concentrated solution is around 36%, but I believe we will use more appropriate 0.1N (or 0.1M) solution. The amount will be around 100 mL.
Hope no math mistakes.
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