question: continued
Ok this is what I've done:
rx 1) M2CO3 +2HCL ->2MCL + CO2 + H20
rx 2) HCL + NaOH -> NaCl + H20
Mole acid added: (.015L)(.1789M)= .00268 mole HCL in 20 ml of solution
mole acid in excess (.1013M) (.01756L) NaOH = .001778 mole HCL
.00268-.001778 = .0009 mole HCL reacted with M2CO3 in 20 ml
moles of M2CO3 = .5(.0009) = .000452 mol M2CO3
mm= 1.85g/ .000452 = 4093g (wrong!)
2 x M +12+48 = 4093
2M = 4093/2
= 2016.5
obviously wrong...but where??? I have the exact same question with different numbers that works with this procedure...I dont understand!
thanks
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