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Originally Posted by redXI
Okay. Where has that NO3 gone??
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You add solid NaCl to a solution containing Ag(+)-ions and NO3(-)-ions. since NaNO3(-) is soluble in water, it isn't necessary to write NO3(-) in the reaction equation, since NaNO3(aq) = Na(+)(aq) + NO3(-)(aq)
So we would get:
NaCl(s) + Ag(+) + NO3(-) --> Na(+) + NO3(-) + AgCl(s)
This is equal to:
NaCl(s) + Ag(+) --> Na(+) + AgCl(s)