As usual, I asked a question and shortly after figured out a possible solution...but just in case, could someone reassure me that this is correct? I'll use names instead of formulas due to lack of subscripts and stack the normally horizontal calculations. Dashed lines signify fractions.
Of course, this is only the first equation, but as long as it's correct then I can fill in the rest.
.0020 L Amm. Phosphate
X
1.50M Amm. Phosphate
----------------------------
1L Amm. Phosphate
X
1M Iron (II) Phosphate
----------------------
2M Amm. Phosphate
X
357.48g Iron (II) Phosphate
-------------------------
1M Iron (II) Phospate
= 0.536 Iron (II) Phosphate
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