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Old January 9th, 2010, 15:16
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Paul Robbins Paul Robbins is offline
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Now looking at your third example:

1.00 g of potassium chloride in 0.500 L of solution.

Again, we need to know number of moles and we need to know volume.

We are told we have 1.00 g of potassium chloride. We convert this into moles using the equation:

number of moles = mass in grams / molecular mass.


Molecular mass of potassium chloride = atomic mass potassium + atomic mass chlorine

= 39.0 + 35.5

= 74.5 g/mol

number of moles = 1.00 / 74.5

= 0.0134228

Then, same as in the first example:

Concentration = moles / volume

= 0.0134228/0.5

= 0.0268 M
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