Hello,
This is how I would solve the following problem.
a-
O3 --- > 1.5 O2
At any time t ,
Pt = Po + 0.5x
r = -d[O3] / dt = -d[P(O3)]/ dt . 1 / RT
dx / dt = r . RT or x = r RT.t
when t = 1.79e-2 s , x = 1.8e-2 mol/L.s x 0.08206 L.atm / mol.K x 483.15 K x 1.79e-2 s = 0.013 atm
Pt = Po +0.5x
Initially Pt = Po
So delta Pt = Pt - Po = 0.5x = 6.5e-3 atm
b-
order = 1.5 then dx / dt = kRT(1.5x)^(3/2) = k'.x^(3/2)
Integrate : -2x^(-0.5) = k'. t or k' is found and then k since we know x = 0.013 atm at t = 1.79e-2 s while R and T are given.
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