got it
its not too hard. You are adding two volumes of the same solution together. SO at the end you have to divide by the new total volume.
First calculate the mols for each solution. Then add them up. Next divide that value by the total volume. Like this:
.0462L (.568mol/L) = .026242mol
.085L (1.396 mol/L) = .11866 mol
.026242 mol + .11866 mol = .144902 mol (total mols in solution)
.0462L + .085L = .1312L (total volume of solution)
Mol/L = molarity(M) = .1144902mol / .1312L = 1.1044
Just remember that you have to deal with the total volume of the new solution. As well as the total amount of mols...
Hope that helped.
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