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Structure and Oxidataion no.
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March 14th, 2006, 01:44
asutoshsahu
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Join Date: Oct 2005
Posts: 3
In Na2S4O6
Na +1
O -2
Then 1x2+4S+(-2)x6=0
Soving this we get O.N. of S=2.5
But in a book it is given that in this molecule
two S atom has O.N. +5 (i.e. 5+5 = 10 ) and the other two S has zero O.N
.
Any comments on this.....
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