there is only half the amount of mols base needed to neutralize the acid --> the base needs to be capable of taking up 2 protons.
--> C
(B is an acid and therefore wrong. KOH will dissolve yielding 1 mol OH(-) per mol KOH and NH3 can take up only 1 proton.
--> Sr(OH)2 yields two mol OH(-) per mol Sr(OH)2 and therefore only half the amount of mol Sr(OH)2 is needed two neutralize the acid)
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