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Halonothing April 29th, 2005 07:27

Calculate the mass of each product
 
Alright i have a dumb question, so i apologize in advance. I'm doing my chem homework, and one of the questions that my prof. wrote, i dont quite grasp.

. "For the following unbalanced equation calculate the mass of each product if 1.55 gram of CS2 is completely reacted:

CS2 + O2 ---> CO2 + SO2"


Atomic masses:
C = 12.011
S = 32.06
O = 16

so i balance the equation.

CS2 + 2(O2) ---> CO2 + (SO)2

now, I check to see how many moles correspond to 1.55 grams of CS2
=
.00828 mol CS2

then

( 2 mol O2 / .00828 mol CS2 ) = 241.5458 . . .

now what? i've been doing this assignment for way way too long. its 5:24 a.m someone save me pleeeeeeeease. what's really throwing me off is the 1.55 grams of CS2. and how that relates to the mass of the rest of the products. :( :!:

charco April 29th, 2005 19:31

Quote:

so i balance the equation.

CS2 + 2(O2) ---> CO2 + (SO)2
unfortunately this is not correct, it should read

CS2 + 2(O2) ---> CO2 + 2SO2

Quote:

now, I check to see how many moles correspond to 1.55 grams of CS2
=
.00828 mol CS2
this is correct..

now you simply look at the stoichiometry of the equation to see that 1 mole of CS2 makes 1 mole of CO2 and 2 moles of SO2

therefore:
0.00828 mol CS2 makes 0.00828 mol of CO2
and 2x 0.00828 mol of SO2

Now calculate masses from mass = moles x RMM

the oxygen is irrelevant providing there is enough (you are not asked for it)


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