specific heat capacity of ice ...
 

hi! what is the specific heat capacity (heat fusion) of ice?

this is just one part of a greater problem I would really appreciate an explanation for ..
here goes ...

water and ice co-exist (or something like that ...) at 0 degrees celsius. So, i have water and ice at 0 degrees celsius in a calorimeter, and the ice weighs 50 grams. I know that when a 35 gram metal ball, at 100 degrees celsius with a specific heat capacity of .442J/gXdegrees celsius is placed in this ice/water solution, the heat released from the metal ball will only go into the ice to heat the ice (heat does not effect the water, it just goes to the ice and melts the ice ..). So, in the end, we have our ice that was first 50 grams, now melted to 48 grams. And the metal ball has gone from 100 degrees to 0 degrees.

How can I measure the specific heat capacity of this ice. I know that the ball released 1547 juoles of energy (q=m X C X change in temp). But, im stuck on calculating the heat capacity needed to raise 1g of ice by 1 degree celsius.

all help is appreciated ... thank you

you do not need the specific heat of ice only that of water and the latent heat of fusion of ice (which you work out)

Energy lost by the metal ball = energy used to melt 2g of ice

m.c.deltaT(ball) = sp latent heat of fusion x m/RMM (ice)

take it from there...